BPCF 2018 - XIII Београдски фестивал проблемског шаха 2018.
Belgrade Internet Tournaments 2018
Group B – h#2 ,
Helpmate in two moves
Judge: Borislav Gadjanski
The thematic condition was the display of „antagonistic pairs“ of
solutions in an h#2. This sort of theme contains elements of paradox in its basic definition, so it was interesting
to see what would be the composers’ creative answer to this challenge.
The package that I got on the 20th May from the neutral judge, Marko Ložajić, blew me away. Twenty high-quality
compositions represent a reponse beyond all expectations and a confirmation that the choice of theme hit the jackpot.
In such a situation and tight deadlines it is never easy to make a choice and rank the compositions in a way that
causes the fewest possible negative comments. When faced with a wealth of compositions that completely satisfy the
theme, the taste, personal inclinations and prejudices of the judge gain in importance, and this is precisely what
happened here. I had to eliminate a composition which I had long considered for one of the top spots, that is B-6
(Kg1/Kd5). The reason is the existence of a complete ideal predecessor (see Annex A, in the right column).
I gave advantage to those compositions, in which the antagonism in the strategy is clear and easily noticeable.
The commendations are unordered.
Many thanks to Marko Ložajić for translation into English!
After the claims, the Awards have been changed! Final version is:
Thematic condition
Antagonistic pairs
Two pairs of solutions in h#2 present some kind of opposite tactical effects. Composers are free to use their imagination with a help of following examples.
Example 1
Fadil ABDURAHMANOVIĆ
3.Pr. Sakkélet 1997
white Ph3 Kf8 Re8 Bh4b1
black Pg6g5d4f2 Kf4 Bc4c1
h#2
4.1.1.1
(5+7)
1.Kf4-f3 Re8-e1 2.Bc1-f4 Bb1-e4# 1.f2-f1=R Bb1*g6 2.Rf1-f3 Re8-e4# 1.Bc4-e2 Bb1-e4 2.Kf4-e3 Bh4*g5# 1.g5-g4 Re8-e4 + 2.Kf4-f5 h3*g4#
In the 1st pair wR & wB support each other to allow mates on e4. In the 2nd pair wR & wB interfere with each other on the critical square e4.
Example 2
Fadil ABDURAHMANOVIĆ
Živko JANEVSKI
2.Pr. Problemist Ukraini 2015
white Ph5g4 Kd7 Rd6 Bd4
black Bg7 Kg5 Qb4 Pc7c5f5h3e2 Sc4c2 Rh7d2
h#2
4.1.1.1
(5+12)
1.f5-f4 Bd4-f2 2.Sc2-d4 Rd6-g6 # 1.Kg5-h4 Rd6-g6 2.Sc4-d6 Bd4-f2 # 1.c7*d6 Bd4-e5 2.Kg5-h6 Be5-f4 # 1.c5*d4 Rd6-d5 2.Kg5-f6 Rd5*f5 #
In the 1st pair of solutions black “liquidates” thematic white pieces. In the 2nd pair black “revives” the same white pieces through unpinning.
Example 3
Fadil ABDURAHMANOVIĆ
1.Pr. J. Elbaz 60 JT 2017
white Qd2 Pa5d5 Kh6 Bg5
black Pa6b5c3 Kc4 Bf3c1 Sb2 Rg2
h#2
4.1.1.1
(5+8)
1.Kc4-b4 Qd2-f4+ 2.Kb4*a5 Bg5-d8 # 1.Bf3-d1 Bg5-e3 2.Bd1-b3 Qd2-d4 # 1.Kc4-c5 Qd2-d3 2.Rg2-d2 Bg5-e7 # 1.Bf3*d5 Bg5-f6 2.Rg2-g5 Qd2*c3 #
White avoids self-pin (see dual-avoidance moves) in the 1st pair. In the 2nd pair white allows self-pin (counting on unpinning by black).
Winners
Fadil Abdurahmanović
Vitaly Medintsev
Aleksandr Semenenko
Zoran Gavrilovski
Participants
Fadil Abdurahmanović (BIH) 2
Zoran Gavrilovski (MKD)
Živko Janevski (MKD)
Marko Klasinc (SLO)
Vasyl Kryzhanivskyi (UKR)
Luis Miguel Martín (ESP)
Vitaly Medintsev (RUS) 2
Dieter Müller (GER) 2
Emanuel Navon (ISR) 2
Abdelaziz Onkoud (MAR)
Aleksandr Semenenko (UKR)
Anatoly Skripnik (RUS) 2
Nikola Stolev (MKD)
Menachem Witztum (ISR) 2
14 names
from 9 countries
Annex
A : Valery Gurov
3-4.Pr. Problemist Ukraini 2015
white Pf2e2f3h5d6 Kc2 Ba2b6 Rf7
black Pb4g5g7d7 Sf4d8 Bg2 Ke5 Rb5
h#2
4.1.1.1
(9+9)
1.Rb5-d5 e2-e4 2.Rd5*d6 Rf7-f5 # 1.Sd8-b7 e2-e3 2.Sb7*d6 Bb6-d4 # 1.Rb5*b6 Rf7-f5 + 2.Ke5-d4 e2-e3 # 1.Sd8*f7 Bb6-d4 + 2.Ke5-f5 e2-e4 #
B : Michal Dragoun
Pr. The Problemist 2007
Album FIDE 2007-09
white Pc4f4 Kd8 Ba8g7 Se5 Rg3
black Bh8 Kd4 Qh6 Pe7b5b3 Sc1 Rd2
h#2
4.1.1.1
(7+8)
1.Sc1-d3 Ba8-d5 2.Sd3-c5 Se5-c6 # 1.b5*c4 Se5-f3 + 2.Kd4-d3 Sf3-d4 # 1.Qh6*f4 Se5-c6 + 2.Kd4-e4 + Sc6-d4 # 1.Qh6-c6 Rg3-c3 2.Qc6-c5 Se5-f3 #
C : Fadil Abdurahmanović
2. Pr. MAT 1980
Album FIDE 1980-82
white Qh8 Pg5a4f4 Kf8 Rc8d4 Bc4
black Qh3 Pg6b3d3e3 Kc3 Be2
h#2
2.1.1.1
(8+7)
1.Qh3*c8 + Rd4-d8 + 2.Kc3*c4 Qh8-d4 # 1.Qh3*h8 + Bc4-g8 + 2.Kc3*d4 Rc8-c4 #
D : Michal Dragoun
Probleemblad 1993
white Qe8 Pd5c4 Kc7 Re6f5 Bg6e5
black Bf7 Ke4 Qg8 Pb7d4f4g4 Sc6h6 Rh7c5
h#2
2.1.1.1
(8+11)
1.Bf7*e6 + Rf5-f7 + 2.Ke4*e5 Qe8*e6 # 1.Bf7*g6 + Be5-g7 + 2.Ke4*f5 Qe8*g6 #
E : József Korponai
1.Pr. Schach-Echo 1970-I
Album FIDE 1968-70
white Pc5 Sg4b3 Bg8 Ke1 Rd1
black Bd4 Kd5 Qg6 Pe2 Sc6 Re6
h#2
b)Sb3→g7
(8+11)
a) 1.Qg6-d3 Bg8-h7 2.Bd4-e5 Sg4-e3 # b) wSb3-->g7 1.Qg6-f7 Rd1-c1 2.Re6-e5 Sg4-f6 #
F : Fadil Abdurahmanović
Živko JANEVSKI
The Problemist 2016
white Qg2 Kf8 Bd7
black Pg6c5f3g3 Re4 Ba6d4 Ke3
h#2
4.1.1.1
(3+8)
1.Bd4-e5 Bd7-b5 2.Ke3-d4 Qg2-d2 # 1.Re4-e5 Bd7-g4 2.Ke3-e4 Qg2*f3 # 1.Ke3-f4 Qg2-b2 2.Bd4-e3 Qb2-f6 # 1.Ke3-d3 Bd7-a4 2.Re4-e3 Qg2-c2 #
BPCF2018B - Award
1st Prize
Fadil Abdurahmanović, BIH
white Pa4f5c3d3 Ke2 Rc8 Se8g6
black Qh1 Pb4b5h4g7 Kd5 Rg4h2 Bf2h5
h#2
4 sol.
(8+10)
1.Bf2-g3 + Ke2-e3 2.Bg3-e5 Sg6-e7 #
1.Rg4-e4 + Ke2-d2 2.Re4-e5 Sg6-f4 #
1.Bh5*g6 c3*b4 2.Rg4-d4 Rc8-c5 #
1.Rh2-h3 a4*b5 2.Bf2-d4 c3-c4 #
A complex and extremely harmonious strategy with a clear and impeccably realized thematic condition with the active role of the WK.
In the first pair, black achieves a self-block by performing a battery attack on the WK. Contrastingly, in the second pair, the same goal is attained by first avoiding to check the opponent by removing the rear pieces of black batteries.
It is especially effective that in the second two solutions, black blocks the square that is controlled by a WP. The pawn gives up control of the d4 square, once in the first, and once in the second (mating) move. By blocking the d4 square, black simultaneously builds a Grimshaw interference. A similar effect is seen in the first pair when, with the use of a self-block, black enables the WS to give up control of the e5 square and mate the BK, and dual mates are avoided by the very blocking piece (R or B).
FEN: 2R1N3/6p1/6N1/1p1k1P1b/Pp4rp/2PP4/4Kb1r/7q
(C+ by Popeye)
2nd Prize
Vitaly Medintsev, RUS
white Qh7 Pe5b4 Sc6g5 Rd8 Ka1
black Pb7e7e6h6c4c3e3f3 Sd6f5 Re2 Kd3
h#2
4 sol.
(7+12)
1.h6*g5 Rd8*d6 + 2.Kd3-e4 Rd6-d4 #
1.b7*c6 Qh7*f5 + 2.Kd3-d4 Qf5-e4 #
1.Re2-d2 Sg5-e4 2.Sf5-g3 Se4*g3 #
1.c3-c2 Sc6-d4 2.Sd6-b5 Sd4*b5 #
A complex and harmonious strategy with intertwining of opposite effects. In the first pair of solutions WSg5/WSc6 are captured passively, and BSf5/BSd6 do not play, whereas in the second pair, both pairs of knights are active. Also, in the first pair, in B1 black self-frees the field for the BK (flight-giving key), while in the second pair, in the B1 black occupied square (self-block key).
FEN: 3R4/1p2p2Q/2Nnp2p/4PnN1/1Pp5/2pkpp2/4r3/K7
(C+ by Popeye)
3rd Prize
Aleksandr Semenenko, UKR
white Pf2 Kc2 Be7 Se2g4
black Rh3f8 Kd5 Bc4 Sg6b5 Pe6f5e3a2h4
h#2
4 sol.
(5+11)
1.Sb5-a7 f2*e3 2.Sa7-c6 Se2-c3 #
1.Rf8-c8 f2-f4 2.Rc8-c6 Sg4-f6 #
1.Rh3-h1 Se2-c3 + 2.Kd5-d4 f2*e3 #
1.Sg6-h8 Sg4-f6 + 2.Kd5-e5 f2-f4 #
Two pairs of reciprocal white moves, where white preserves control over the square next to the BK by switching the piece controlling the square, whereas in the second pair frees the square for the arrival of the bK. Wonderful hideaways of black pieces in the 2nd pair of solutions.
FEN: 5r2/4B3/4p1n1/1n1k1p2/2b3Np/4p2r/p1K1NP2/8
(C+ by Popeye)
4th Prize
Zoran Gavrilovski, MKD
white Ke3 Rg5 Sg3 Bh2f3
black Ba2 Kd6 Qd1 Pb6b4 Sb3a5 Rh7h1
h#2
4 sol.
(5+9)
1.Qd1-a1 Sg3-e4 + 2.Kd6-c6 Se4-f6 #
1.Qd1-f1 Sg3-f5 + 2.Kd6-c5 Sf5-d6 #
1.Sb3-c5 Rg5-g7 2.Ba2-e6 Sg3-f5 #
1.Sa5-c6 Bf3-g4 2.Rh7-e7 + Sg3-e4 #
In the first pair of solutions the BK arrives on the c5 and c6 squares, and in the second pair these squares are blocked by the black knights. In the first pair, the BQ unexpectedly moves away in the first move, and in the second pair, aside from thematic self-blocks by the knights, we have additional self-blocks of the R and B.
I was exhilarated by white’s play. In the first pair white opens the battery along the h2-c8 diagonal and builds new B/S and R/S batteries with which he mates black. In the second pair, the rear pieces of the batteries from the first pair reciprocally (in relation to the BR and BB) control the e7 and e6 squares, while the initial Bh2/Sg3 battery delivers the mates. Unfortunately, a very similar white play already exists (Annex B), but with a different black and with the W1 moves a differently motivated play. Heavyhearted, I had to, after the initial publication of the results, demote this problem with a paradoxical “unity of opposites” and rich battery play from the top spot.
FEN: 8/7r/1p1k4/n5R1/1p6/1n2KBN1/b6B/3q3r
(C+ by Popeye)
Spec. Prize
Fadil Abdurahmanović, BIH
white Qa4 Kd1 Bc1
black Pb5d7e4f7h5 Kf5 Rf6 Be6h2
h#2
4 sol.
(3+9)
1.Be6-a2 Bc1-f4 2.Kf5-e6 Qa4*e4 #
1.Rf6-h6 Qa4*b5 + 2.Kf5-f6 Qb5-g5 #
1.Kf5-g6 Qa4-a8 2.Be6-f5 Qa8-g8 #
1.Kf5-e5 Bc1-e3 2.Rf6-f5 Qa4-d4 #
Perfect elegance! This Meredith shows a pure unblock in the first pair of solutions, enabling the arrival of the BK. By its departure, both the Be6 and the Rf6 completely lose their roles. In the second pair the same pieces arrive on the f5 square, vacated by the BK – pure self-blocks. In other words, here we can see two pairs of reciprocal freeing: BB-BK and BR-BK. All the mates are delivered by the WQ, and the WB helps her – twice actively and twice passively. A similar mechanism, but with a different strategy, was seen two years earlier. (Annex F)
FEN: 8/3p1p2/4br2/1p3k1p/Q3p3/8/7b/2BK4
(C+ by Popeye)
1st Hon. Mention
Menachem Witztum, ISR
white Ph5h4d2b3 Kb5 Bd7b2 Sf7
black Ba1d3 Ke4 Qf4 Pc4b6b7e3 Sh3 Rg6c2
h#2
4 sol.
(8+11)
1.Rc2-c3 Bd7-c6 + 2.Ke4-d4 d2*c3 #
1.Rg6-e6 Sf7-g5 + 2.Ke4-f5 Bd7*e6 #
1.Ke4-d5 Bb2-c3 2.Bd3-e4 b3*c4 #
1.Qf4-f3 Bd7-e6 2.Sh3-f4 Sf7-d6 #
Black-white interferences of line pieces is a natural idea for displaying opposing effects, but is likely difficult to execute in a perfect form. The author found a very good scheme here which is slightly marred by the pair of pawns which are playing as extras in one pair of solutions each.
FEN: 8/1p1B1N2/1p4r1/1K5P/2p1kq1P/1P1bp2n/1BrP4/b7
(C+ by Popeye)
2nd Hon. Mention
Vitaly Medintsev, RUS
white Qa8 Pb3g5f5d6a7 Rd5e8 Be5 Kc7
black Pc3g7 Ke4 Bb1 Rb4d8
h#2
4 sol.
(10+6)
1.Rd8*a8 Be5*c3 + 2.Ke4*d5 Re8-e5 #
1.Rd8*e8 Rd5-d4 + 2.Ke4*e5 Qa8-d5 #
1.Ke4-f3 Be5-g3 2.Rb4-g4 Rd5-d3 #
1.Ke4-e3 Rd5-d1 2.Rb4-f4 Be5-d4 #
An outstanding display of a combination of pairs with destruction of a white battery and play of the same battery in which the passive Zilahi naturally occurs. The mechanism of the first pair is not new (see Annex C & D)
The author has improved these mechanisms by adding two phases with very original battery play, culminating in mate by double check.
FEN: Q2rR3/P1K3p1/3P4/3RBPP1/1r2k3/1Pp5/8/1b6
(C+ by Popeye)
3rd Hon. Mention
Emanuel Navon, ISR
white Pa4e6 Kb7 Rb5 Sc5
black Bh8h1 Kc4 Qg7 Pd3d4c3a3d7b6e4f6 Sd1c8 Rf7e7
h#2
4 sol.
(5+16)
1.f6-f5 Sc5*d3 2.Rf7-f6 Sd3-e5 #
1.c3-c2 Sc5-b3 2.Sd1-c3 Sb3-d2 #
1.Re7-e8 Sc5*d7 2.Sc8-e7 Sd7*b6 #
1.Sc8-a7 Sc5*e4 2.Sa7-c6 Se4-d6 #
The thematic condition completely realized by the play of just one white piece! In the first pair white avoids a self-pin, while black removes control over the mating square and for this “help” needs two moves in each phase. In the second pair, completely paradoxically and in contrast to the first pair, white performs the self-pin! Black, on the other hand, again offers the necessary two-move assistance in order to “mitigate the damage” caused by the white knight’s self-pin. The white knight mates in all four solutions and on four different squares.
FEN: 2n4b/1K1prrq1/1p2Pp2/1RN5/P1kpp3/p1pp4/8/3n3b
(C+ by Popeye)
4th Hon. Mention
Menachem Witztum, ISR
white Pg4f4f5e2d4c4 Sf3g6 Re7 Kg1 Bb6
black Bg2b8 Ke3 Qe4 Pd3c3b7d7d6 Sh1e6 Rb5b4
h#2
4 sol.
(11+13)
1.Bg2-f1 Kg1*f1 2.Se6*d4 Bb6*d4 #
1.Qe4-c6 d4-d5 + 2.Ke3-e4 Sf3-g5 #
1.Qe4*d4 f5*e6 2.Qd4-c5 e6*d7 #
1.Qe4-e5 d4*e5 + 2.Se6-c5 e5*d6 #
In the first pair the mate occurs on the pinned piece from a half-pin system. In the second pair, the mate again occurs on a pinned piece from a half-pin system, but the piece is pinned along another type of line (diagonally). The mate is a battery one, activated by the pawn battery that appears after the capture of the rear piece in the half-pin system. A good and very complex strategy. The solution pairs are intrinsically different, however there is no clear antagonism.
FEN: 1b6/1p1pR3/1B1pn1N1/1r3P2/1rPPqPP1/2ppkN2/4P1b1/6Kn
(C+ by Popeye)
5th Hon. Mention
Emanuel Navon, ISR
white Kg1 Re1h4 Se4b7
black Bb1h8 Kd5 Qa1 Pd4c3f5f7d7c6 Se5 Rf6h5
h#2
4 sol.
(5+13)
1.Se5-d3 Re1-e2 2.Kd5-e5 Se4*c3 #
1.d4-d3 Rh4-f4 2.Kd5-d4 Se4*f6 #
1.f5*e4 Re1*e4 2.Rf6-e6 Re4*d4 #
1.Bb1*e4 Rh4*e4 2.Kd5-e6 Re4*e5 #
Very good change of play, however one in which the opposing strategies are not pronounced enough.
FEN: 7b/1N1p1p2/2p2r2/3knp1r/3pN2R/2p5/8/qb2R1K1
(C+ by Popeye)
Spec. Hon. Mention
Anatoly Skripnik, RUS
white Qb1 Ka1 Re1
black Ph2d6d7b5 Kg8 Rh1
h#2
4 sol.
(3+6)
1.Kg8-f7 Re1-f1 + 2.Kf7-e6 Qb1-e4 #{
1... Qg6? 2.Kf8 Re8??}
1.Kg8-g7 Re1-g1 + 2.Kg7-h6 Qb1-g6 #{
1... Re7? 2.Kh8 Qh7??}
1.Rh1-f1 Re1-e7 2.Rf1-f8 Qb1-h7 #
1.Rh1-g1 Qb1-f5 2.Rg1-g7 Re1-e8 #
A solid attempt at displaying the theme in Meredith form.
White avoids self-pin in the 1st pair.
In the 2nd pair white allows self-pin (counting on unpinning by black).
FEN: 6k1/3p4/3p4/1p6/8/8/7p/KQ2R2r
(C+ by Popeye)
Commend.
Živko Janevski, MKD
white Pd4 Kd2 Rg5 Bb5
black Pf4e5c4 Kd5 Be7h3 Sa7
h#2
4 sol.
(4+7)
1.Kd5*d4 Bb5-c6 2.e5-e4 Rg5-d5 #
1.Kd5-e4 Bb5*c4 2.e5*d4 Bc4-d5 #
1.Bh3-d7 d4*e5 2.Kd5-e6 Bb5*c4 #
1.Sa7-c8 Kd2-c3 2.Sc8-d6 Rg5*e5 #
Capturing of the white Pd4 in the first pair of solutions and capturing of the black Pe5 in the second pair of solutions. The reciprocal capturing of pawns in solutions II & III connects both thematic pairs of solutions! The thematic wPd4 is superfluous in the first solution!
FEN: 8/n3b3/8/1B1kp1R1/2pP1p2/7b/3K4/8
(C+ by Popeye)
Commend
Marko Klasinc, SLO
white Qf7 Pc6 Kh3 Re6
black Bf8 Kc5 Qd7 Pb7b6d4 Sg7a7 Rd8
h#2
4 sol.
(4+9)
1.Qd7-c7 Re6-e5 + 2.Kc5-d6 Qf7-d5 #
1.Qd7-d6 Re6-e4 2.d4-d3 Qf7-c4 #
1.Kc5-d5 Qf7-f2 2.Bf8-c5 Qf2-a2 #
1.Bf8-d6 Qf7-f1 2.Kc5*c6 Qf1-c4 #
Basic idea: how to get the white queen onto the a2-d5 diagonal.First pair: 2 x gate opening after unpinning of the white rook. Second pair: 2 x peri-manoeuvre of the white queen.
4 effective phases in a light position, but with a less pronounced antagonism in the solutions.
FEN: 3r1b2/np1q1Qn1/1pP1R3/2k5/3p4/7K/8/8
(C+ by Popeye)
Commend
Vasyl Kryzhanivskyi, UKR
white Kh2 Pc4a3e3f3a4 Ba5 Rc8 Sg2
black Qf4 Pb3 Kd3 Be1 Sg3b2
h#2
4 sol.
(9+6)
1.Be1-b4 Sg2-e1 + 2.Kd3-c3 Ba5*b4 #
1.Qf4-c7 Sg2-f4 + 2.Kd3*c4 Rc8*c7 #
1.Qf4*c4 Rc8-e8 2.Sg3-e2 Sg2*e1 #
1.Sb2*c4 Ba5-b6 2.Sc4-d2 Sg2*f4 #
An ambitious composition where the black play is not entirely analogous. Namely, in the second pair, in one phase, the c4 square which was accessed by the black king is blocked by the black queen, whereas in the second phase the c3 square is controlled by the white rook
FEN: 2R5/8/8/B7/P1P2q2/Pp1kPPn1/1n4NK/4b3
(C+ by Popeye)
Commend
Dieter Müller, GER
white Pa5e7h7 Ka2 Be5d7 Sb5c3
black Pa4 Kb4 Be8h8
h#2
4 sol.
(8+4)
1.Kb4-c5 Bd7-e6 2.Be8-c6 Be5-d6 #
1.Kb4*a5 Be5-c7 + 2.Ka5-a6 Bd7-c8 #
1.Be8*d7 e7-e8=Q 2.Bd7*b5 Qe8*b5 #
1.Bh8*e5 h7-h8=Q 2.Be5*c3 Qh8*c3
WPe7 and WPh7, which are unneeded in the first pair, get one role each in the second pair of solutions.
FEN: 4b2b/3BP2P/8/PN2B3/pk6/2N5/K7/8
(C+ by Popeye)
Commend
Abdelaziz Onkoud, MAR
white Pg4h7 Se2d7 Bg6 Kg1 Rc4
black Bd4f1 Ke4 Qg8 Pf7b5c5c2f3 Se3 Rf5
h#2
4 sol.
(7+11)
1.b5*c4 Bg6*f7 2.Bd4-e5 Sd7*c5 #
1.f7*g6 Rc4-c3 2.Rf5-e5 Sd7-f6 #
1.Bf1*e2 h7-h8=Q 2.Be2-d3 Qh8-e5 #
1.c2-c1=S h7*g8=S 2.Sc1-d3 Sg8-f6 #
The mechanism of the first pair, in numerous variations, has already been seen many times. One of the older examples is presented in Annex – E. The second pair is achieved with the help of the Ph7, which is no role in the first pair of solutions.
FEN: 6q1/3N1p1P/6B1/1pp2r2/2Rbk1P1/4np2/2p1N3/5bK1
(C+ by Popeye)
Commend
Anatoly Skripnik, RUS
white Rf3 Kc4 Bc2g7 Pg3h6
black Rf4a3 Kf5 Be4c1 Pd4g6h5
h#2
4 sol.
(6+8)
1.Be4*c2 Rf3-e3 2.Rf4-g4 Re3-e5 #
1.Rf4*f3 Bc2-a4 2.Bc1-g5 Ba4-d7 #
1.Ra3-e3 Bc2*e4 + 2.Kf5*e4 Rf3*f4 #
1.g6-g5 Rf3*f4 + 2.Kf5-g6 Bc2*e4 #
Reciprocal captures + Zilahi. The roles some of the pieces are not completely balanced.
FEN: 8/6B1/6pP/5k1p/2Kpbr2/r4RP1/2B5/2b5
(C+ by Popeye)
Commend
Nikola Stolev, MKD
white Qa3 Pb4b5c4g4h3 Ka2
black Ke6 Pd5d4e7f6g6a7 Bc5f5 Re5d6 Sc7
h#2
4 sol.
(7+12)
1.Bf5*g4 Qa3-g3 2.Ke6-f5 Qg3*g4 #
1.Rd6-c6 Qa3-a6 2.Ke6-d6 Qa6*c6 #
1.Rd6-d7 g4*f5 + 2.Ke6-d6 b4*c5 #
1.Bf5-e4 c4*d5 + 2.Ke6*d5 Qa3-b3 #
Display of the theme in which the WQ plays the main role, but in the second pair we do not have a complete analogy.
FEN: 8/p1n1p3/3rkpp1/1Pbprb2/1PPp2P1/Q6P/K7/8
(C+ by Popeye)
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